3.576 \(\int x (a+b \log (c (d+e x^{2/3})^2))^p \, dx\)

Optimal. Leaf size=350 \[ \frac {3 d^2 2^{p-1} e^{-\frac {a}{2 b}} \left (d+e x^{2/3}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \Gamma \left (p+1,\frac {-a-b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{2 b}\right )}{e^3 \sqrt {c \left (d+e x^{2/3}\right )^2}}+\frac {2^{p-1} 3^{-p} e^{-\frac {3 a}{2 b}} \left (d+e x^{2/3}\right )^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{2 b}\right )}{e^3 \left (c \left (d+e x^{2/3}\right )^2\right )^{3/2}}-\frac {3 d e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )}{2 c e^3} \]

[Out]

2^(-1+p)*(d+e*x^(2/3))^3*GAMMA(1+p,-3/2*(a+b*ln(c*(d+e*x^(2/3))^2))/b)*(a+b*ln(c*(d+e*x^(2/3))^2))^p/(3^p)/e^3
/exp(3/2*a/b)/(c*(d+e*x^(2/3))^2)^(3/2)/(((-a-b*ln(c*(d+e*x^(2/3))^2))/b)^p)-3/2*d*GAMMA(1+p,(-a-b*ln(c*(d+e*x
^(2/3))^2))/b)*(a+b*ln(c*(d+e*x^(2/3))^2))^p/c/e^3/exp(a/b)/(((-a-b*ln(c*(d+e*x^(2/3))^2))/b)^p)+3*2^(-1+p)*d^
2*(d+e*x^(2/3))*GAMMA(1+p,1/2*(-a-b*ln(c*(d+e*x^(2/3))^2))/b)*(a+b*ln(c*(d+e*x^(2/3))^2))^p/e^3/exp(1/2*a/b)/(
((-a-b*ln(c*(d+e*x^(2/3))^2))/b)^p)/(c*(d+e*x^(2/3))^2)^(1/2)

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Rubi [A]  time = 0.45, antiderivative size = 347, normalized size of antiderivative = 0.99, number of steps used = 12, number of rules used = 7, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {2454, 2401, 2389, 2300, 2181, 2390, 2310} \[ \frac {3 d^2 2^{p-1} e^{-\frac {a}{2 b}} \left (d+e x^{2/3}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{2 b}\right )}{e^3 \sqrt {c \left (d+e x^{2/3}\right )^2}}+\frac {2^{p-1} 3^{-p} e^{-\frac {3 a}{2 b}} \left (d+e x^{2/3}\right )^3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{2 b}\right )}{e^3 \left (c \left (d+e x^{2/3}\right )^2\right )^{3/2}}-\frac {3 d e^{-\frac {a}{b}} \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p} \text {Gamma}\left (p+1,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )}{2 c e^3} \]

Antiderivative was successfully verified.

[In]

Int[x*(a + b*Log[c*(d + e*x^(2/3))^2])^p,x]

[Out]

(2^(-1 + p)*(d + e*x^(2/3))^3*Gamma[1 + p, (-3*(a + b*Log[c*(d + e*x^(2/3))^2]))/(2*b)]*(a + b*Log[c*(d + e*x^
(2/3))^2])^p)/(3^p*e^3*E^((3*a)/(2*b))*(c*(d + e*x^(2/3))^2)^(3/2)*(-((a + b*Log[c*(d + e*x^(2/3))^2])/b))^p)
- (3*d*Gamma[1 + p, -((a + b*Log[c*(d + e*x^(2/3))^2])/b)]*(a + b*Log[c*(d + e*x^(2/3))^2])^p)/(2*c*e^3*E^(a/b
)*(-((a + b*Log[c*(d + e*x^(2/3))^2])/b))^p) + (3*2^(-1 + p)*d^2*(d + e*x^(2/3))*Gamma[1 + p, -(a + b*Log[c*(d
+ e*x^(2/3))^2])/(2*b)]*(a + b*Log[c*(d + e*x^(2/3))^2])^p)/(e^3*E^(a/(2*b))*Sqrt[c*(d + e*x^(2/3))^2]*(-((a
+ b*Log[c*(d + e*x^(2/3))^2])/b))^p)

Rule 2181

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(F^(g*(e - (c*f)/d))*(c +
d*x)^FracPart[m]*Gamma[m + 1, (-((f*g*Log[F])/d))*(c + d*x)])/(d*(-((f*g*Log[F])/d))^(IntPart[m] + 1)*(-((f*g*
Log[F]*(c + d*x))/d))^FracPart[m]), x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 2300

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Dist[x/(n*(c*x^n)^(1/n)), Subst[Int[E^(x/n)*(a +
b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, n, p}, x]

Rule 2310

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*n*(c*x^n
)^((m + 1)/n)), Subst[Int[E^(((m + 1)*x)/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, d, m, n, p}
, x]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2401

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Int[Exp
andIntegrand[(f + g*x)^q*(a + b*Log[c*(d + e*x)^n])^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[
e*f - d*g, 0] && IGtQ[q, 0]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rubi steps

\begin {align*} \int x \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \, dx &=\frac {3}{2} \operatorname {Subst}\left (\int x^2 \left (a+b \log \left (c (d+e x)^2\right )\right )^p \, dx,x,x^{2/3}\right )\\ &=\frac {3}{2} \operatorname {Subst}\left (\int \left (\frac {d^2 \left (a+b \log \left (c (d+e x)^2\right )\right )^p}{e^2}-\frac {2 d (d+e x) \left (a+b \log \left (c (d+e x)^2\right )\right )^p}{e^2}+\frac {(d+e x)^2 \left (a+b \log \left (c (d+e x)^2\right )\right )^p}{e^2}\right ) \, dx,x,x^{2/3}\right )\\ &=\frac {3 \operatorname {Subst}\left (\int (d+e x)^2 \left (a+b \log \left (c (d+e x)^2\right )\right )^p \, dx,x,x^{2/3}\right )}{2 e^2}-\frac {(3 d) \operatorname {Subst}\left (\int (d+e x) \left (a+b \log \left (c (d+e x)^2\right )\right )^p \, dx,x,x^{2/3}\right )}{e^2}+\frac {\left (3 d^2\right ) \operatorname {Subst}\left (\int \left (a+b \log \left (c (d+e x)^2\right )\right )^p \, dx,x,x^{2/3}\right )}{2 e^2}\\ &=\frac {3 \operatorname {Subst}\left (\int x^2 \left (a+b \log \left (c x^2\right )\right )^p \, dx,x,d+e x^{2/3}\right )}{2 e^3}-\frac {(3 d) \operatorname {Subst}\left (\int x \left (a+b \log \left (c x^2\right )\right )^p \, dx,x,d+e x^{2/3}\right )}{e^3}+\frac {\left (3 d^2\right ) \operatorname {Subst}\left (\int \left (a+b \log \left (c x^2\right )\right )^p \, dx,x,d+e x^{2/3}\right )}{2 e^3}\\ &=-\frac {(3 d) \operatorname {Subst}\left (\int e^x (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{2 c e^3}+\frac {\left (3 \left (d+e x^{2/3}\right )^3\right ) \operatorname {Subst}\left (\int e^{3 x/2} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{4 e^3 \left (c \left (d+e x^{2/3}\right )^2\right )^{3/2}}+\frac {\left (3 d^2 \left (d+e x^{2/3}\right )\right ) \operatorname {Subst}\left (\int e^{x/2} (a+b x)^p \, dx,x,\log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{4 e^3 \sqrt {c \left (d+e x^{2/3}\right )^2}}\\ &=\frac {2^{-1+p} 3^{-p} e^{-\frac {3 a}{2 b}} \left (d+e x^{2/3}\right )^3 \Gamma \left (1+p,-\frac {3 \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )}{2 b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p}}{e^3 \left (c \left (d+e x^{2/3}\right )^2\right )^{3/2}}-\frac {3 d e^{-\frac {a}{b}} \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p}}{2 c e^3}+\frac {3\ 2^{-1+p} d^2 e^{-\frac {a}{2 b}} \left (d+e x^{2/3}\right ) \Gamma \left (1+p,-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{2 b}\right ) \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \left (-\frac {a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )}{b}\right )^{-p}}{e^3 \sqrt {c \left (d+e x^{2/3}\right )^2}}\\ \end {align*}

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Mathematica [F]  time = 0.30, size = 0, normalized size = 0.00 \[ \int x \left (a+b \log \left (c \left (d+e x^{2/3}\right )^2\right )\right )^p \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[x*(a + b*Log[c*(d + e*x^(2/3))^2])^p,x]

[Out]

Integrate[x*(a + b*Log[c*(d + e*x^(2/3))^2])^p, x]

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fricas [F]  time = 1.23, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (b \log \left (c e^{2} x^{\frac {4}{3}} + 2 \, c d e x^{\frac {2}{3}} + c d^{2}\right ) + a\right )}^{p} x, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(2/3))^2))^p,x, algorithm="fricas")

[Out]

integral((b*log(c*e^2*x^(4/3) + 2*c*d*e*x^(2/3) + c*d^2) + a)^p*x, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )}^{2} c\right ) + a\right )}^{p} x\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(2/3))^2))^p,x, algorithm="giac")

[Out]

integrate((b*log((e*x^(2/3) + d)^2*c) + a)^p*x, x)

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maple [F]  time = 0.08, size = 0, normalized size = 0.00 \[ \int x \left (b \ln \left (\left (e \,x^{\frac {2}{3}}+d \right )^{2} c \right )+a \right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(b*ln((e*x^(2/3)+d)^2*c)+a)^p,x)

[Out]

int(x*(b*ln((e*x^(2/3)+d)^2*c)+a)^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \log \left ({\left (e x^{\frac {2}{3}} + d\right )}^{2} c\right ) + a\right )}^{p} x\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*log(c*(d+e*x^(2/3))^2))^p,x, algorithm="maxima")

[Out]

integrate((b*log((e*x^(2/3) + d)^2*c) + a)^p*x, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x\,{\left (a+b\,\ln \left (c\,{\left (d+e\,x^{2/3}\right )}^2\right )\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*log(c*(d + e*x^(2/3))^2))^p,x)

[Out]

int(x*(a + b*log(c*(d + e*x^(2/3))^2))^p, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*ln(c*(d+e*x**(2/3))**2))**p,x)

[Out]

Timed out

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